Question

A quadratic polynomial whose
one zero is 6 and sum of the zeroes is o, is
a)x² - 6x + 2
b) x²-36
c)x²-6
d) x²- 3.
​

Answer 1

$\huge \mathfrak{answer}$

option b

$\sf \red{ {x}^{2} - 36}$

☆The number when added to 6 will give us 0 is - 6.

☆ so root is -6

☆The roots of the quadratic equation are - 6 and 6.

$\rm \blue{(x - 6)(x +6)}$

$\rm \red{ {x}^{2} - 6x + 6x - 36}$

$\rm \blue{ {x}^{2} - 36}$

so answer is

$\bf{ \huge{ \boxed{ \red{ \tt{ {x}^{2} - 36 \: }}}}}$

Answer 2

Step-by-step explanation:

b is your answer

x²-36

x²-(√36)²=0

(x+√36) (x-√36)=0

x+√36=0. x-√36=0

x=. -√36. x= √36

x= -6 x= 6

bcz , one of the zero is 6

please mark me as brainliest