Question

A quadratic polynomial whose product of zeroes is -36 and sum of the zeroes is 0, is​

Answer 1

Explanation:

Quadratic equations :-x^2 -(α+β)x +αβ.

sum of zeroes = (α+β)

product of zeroes =αβ

after putting values,

= x^2-(-36)x+0

= x^2+36 ans.

Answer 2

${ \huge{ \underline{ \underline{ \sf{ \green{GivEn : }}}}}}$

• Product of zeroes = -36

• Sum of zeroes = 0

${ \huge{ \underline{ \underline{ \sf{ \green{To \: find :}}}}}}$

• What's the quadratic polynomial?

Formula to be used :-

• x² -(α + β)x + αβ

${ \huge{ \underline{ \underline{ \sf{ \green{SoluTion : }}}}}}$

We know,

formula for quadratic polynomial :-

x² -(α + β)x + αβ

Let α and β be the zeroes of required polynomial.

Therefore,

Let α + β = 0

Let αβ = -36

Now, put the given values in the formula for getting the required quadratic polynomial.

x² -(α + β)x + αβ

⟶ x² -(0)x + (-36)

⟶ x² - 0x - 36

⟶ x² - 36

Hence, the required quadratic polynomial is

x² - 36

Know more :-

Quadratic polynomial :

It's a polynomial of degree 2.

formula for quadratic polynomial is ___

x² -(α + β)x + αβ

Where,

(α + β) = sum of zeroes

αβ = product of zeroes