Question

a quadratic polynomial whose zeroes are -3 and 4​

Answer 1

Since Zeroes are -3 and 4.

So polynomial P(x)=

$= {x}^{2} - (soz)x + (poz) \\ ={x}^{2} - ( - 3 + 4)x + ( - 3 \times 4) \\ = {x}^{2} - x - 12$

Hope it is helpful

Answer 2

Answer:

here , quadratic polynomial = x^2- 1x - 12.

Step-by-step explanation:

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