Question

A quadratic polynomial, whose zeroes are -3 and 4, is​

Answer 1

Answer:

x^2 - x - 12 =0

Step-by-step explanation:

sum of zeros (soz) = 1

product of zeros (poz) = -12

quadratic equation = {x^2 - x (soz) + (poz) }

= x^2 - x - 12

hence solved

i hope u will understand..

Answer 2

Answer:

x² - x - 12

Step-by-step explanation:

We know that

Sum of zeroes = α + β &

Product of zeroes = αβ

Let α = 4 and β = -3

Sum = 4 + (-3)

Sum = 4 - 3

Sum = 1

Product = 4 × (-3)

Product = -12

Standard form of quadratic polynomial = x² - (α + β)x + αβ

x² - (1)x + (-12)

x² - x - 12

Hope it helps u.