Question

A quadratic polynomial whose zeroes are -3 and 4 is
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Answer 1

A quadratic polynomial outline is given below:

$\Large \purple {\tt {{x}^{2} + (a+b)x + (a)(b)}}$

Given, a is (-3) and b is 4 as they're the roots.

A quadratic polynomial whose zeroes are -3 and 4 is given below:

$\Large \pink {\tt {{x}^{2} + ( -3 + 4 )x + (-3)(4)}}$

$\huge \purple {\tt {\leadsto {x}^{2} + x - 12}}$

$\Huge \pink {\underline {\mathbb {ANSWER:}}}$

$\Huge \purple {\underline {\tt { {x}^{2} + x - 12}}}$

Answer 2

Answer:

Correct Question:-

Find a Quadratic polynomial whose zeros are -3 and 4.

Given:-

Zeros of a Quadratic polynomial are-3 and 4.

To find:-

The Quadratic polynomial

Solution:-

Let

the zeros are a and b

• a=-3
• b=4

We know that

• if zeros of a Quadratic polynomial are given then the formula to find the Quadratic polynomial is ,

$\boxed{\sf x^2-(a+b)x+ab=0}$

$\\ \sf{:}\longrightarrow x^2-(-3+4)x+(-3)(4)=0$

$\\ \sf{:}\longrightarrow x^2-(1)x+(-12)=0$

$\\ \bf{:}\longrightarrow x^2-x-12=0$