Question

a quadratic polynomial ,whose zeroes are -3 and 4 is

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Answer 1

Hello

Given

Alpha= -3

Beta=4

Quadratic Polynomial

=>. k[x^2-(alpha+beta)x+(alpha*beta)]

=>. k[x^2-(-3+4)x+(-3)(4)]

=>. k[x^2-x-12]

Now.....if k= 1

=>. x^2-x-12

Thus

Required Quadratic Polynomial with zeroes-3 & 4

x^2-x-12

Hope it helps...

Mark as Brainliest plz....

Answer 2

Solution -

The required Zeroes are -3 and 4 .

Sum of Zeroes -

=> -3 + 4

=> 1

Product Of Zeroes -

=> ( -3 )( 4 )

=> -12

Now , a quadratic polynomial can be written as -

x² - ( Sum of Zeroes ) x + ( Product Of Zeroes )

=> x² - ( 1 ) x - 12

=> x² - x - 12

Verification -

x² + x - 12

=> x² - 4x + 3x + 12

=> x ( x - 4 ) + 3 ( x - 4 )

=> ( x + 3 )( x - 4 )

Zeroes -

=> -3, 4

Hence Verified -

Additional Information -

In a Polynomial -

Sum of Zeroes = ( -b / a )

Product Of Zeroes = ( c / a )