Math, asked by tan9arajenium, 1 year ago

A quadratic polynomial , whose zeroes are -3 and 4 is , (A) X square - x + 12 (B) x square + x + 12 (C) x square/2 - x/2 -6 (D) 2x square + 2x - 24 Please solve it .

Answers

Answered by Anonymous
0
Given-Zeroes are 4 and -3
Now,
αβ=4×(-3)
    = -12⇒ -b/a= -(-12)/1
∴,b=12 and a=1
Again,
α+β=4+(-3)
       =1⇒ c/a=1/1
∴c=1 and a=1

So the quadratic polynomial will be of the form ax²+bx+c ,i.e-
x²+12x+1

#Srijoni : 3




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