Math, asked by gauthamnair2005, 9 months ago

A quadratic polynomial, whose zeroes are -3 and 4, is
(a) x²- x + 12
(b) x² + x + 12
(c) 
(d) 2x² + 2x – 24​

Answers

Answered by priyankmrunal
1

Answer:

Zeroes of quadratic polynomial are -3 and 4,

Let a=-3 and b=4

For finding quadratic polynomial from zeroes of polynomial we have a formula,

x^2-(a+b) +ab=x^2-(-3+4)x+(-3)(4)

x^2-x-12=0 is the required quadratic polynomial.

OR

Since -3 and 4 are zeroes of polynomial

So, (x+3) and (x-4) are the factors of the polynomial.

To find the required equation,Multiply both the factors,

(x+3)(x-4)=x(x-4)+3(x-4)

=x^2-4x+3x-12

=x^2-x-12=0

Now, it can also be written as 2x^2-2x-24=0.

Because we can take 2 as common.

So,required quadratic polynomial from the options will be 2x^2-2x-24.

Hence, the answer is (d).

Hope it helps you.

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