A quadratic polynomial, whose zeroes are -3 and 4, is
I want full solution(detailed one )
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Answered by
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Answer:
by this process u can solve.
Step-by-step explanation:
Let the zeroes of the quadratic polynomial be α=
2
2+
5
,β=
2
2−
5
Then, α+β=
2
2+
5
+
2
2−
5
=
2
2+
5
+2−
5
=2
αβ=
2
2+
5
×
2
2−
5
=
4
(2+
5
)(2−
5
)
=
4
4−5
=
4
−1
Sum of zeroes =α+β=2
Product of zeroes =αβ=−
4
1
Then, the quadratic polynomial =x
2
−( sum of zeroes )x+ product of zeroes =x
2
−(2)x+(−
4
1
)
=x
2
−2x−
4
1
=
2
4x
2
−8x−1
We can consider 4x
2
−8x−1 as required quadratic polynomial because it will also satisfy the given conditions.
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