Question

a quadratic polynomial whose zeroes are -3 and 4 is

the option is-☝ in the picture
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Answer 1

Answer:

x2-x-12=0

Step-by-step explanation:

qe=x2-(sum of zeores) +product of zeroes

Answer 2

☘️Solution:-

$→\;{\sf{x = -3\;(or)\;4}}$

$→\;{\sf{(x+3)(x-4)}}$

$→\;{\sf{x²-4x+3x-12}}$

$→\;{\sf{x²-x-12}}$

• Required QE = $\red{\bold{x²-x-12 = 0}}$

$\boxed{\pink{\sf{\star\;QE = x²-(\alpha+\beta)+(\alpha×\beta)}}}$

$\Large{✓}$

Hope It Helps You ✌️