Question

A quadratic polynomial, whose zeroes are –3 and 4, is
x^2 – x - 12
x^2 + x + 12
3X^2-5
2x^2 + 2x –24

Answer 1

       $\underline{\bold{Answer:}}$

       $x^{2} - x - 12$

       $\underline{\bold{Step-by-step-explaination:}}$

       $\text{The given roots are -3 and 4}$

$\implies \text{Sum of roots}= -3 + 4 = 1$

$\implies \text{Product of roots}= (-3)(4) = -12$

       $\text{We know that a quadratic polynomial is of the form:}$

       $x^{2} - (\text{Sum of roots})x + (\text{Product of roots})$

$\implies \text{The polynomial}= x^{2} -(1)x + (-12)$

$\implies \boxed{\text{The polynomial}= x^{2} -x -12}$