Question

A quadratic polynomial whose zeroes are 3 and 4 , then what will be the sum of the zeroes

Answer 1

Answer:

sum of zeros is 7

I think so

Answer 2

Answer:

Sum of zeroes = 7

$qudratic \: equation \: = {x}^{2} - 7x + 12 = 0$

Step-by-step explanation:

$\tt{Let, \: \alpha \: and \: \beta \: be \: the \: zeroes}$

Given :-

$\bull \: \: \: \tt{ \alpha = 3}$

$\bull \: \: \tt{ \beta = 4}$

We know that,

$\bull \: \: \tt{sum \: of \: zeroes \: = 3 + 4 = 7}$

$\bull \: \: \tt{product \: of \: zeroes \: = 3 \times 4 = 12}$

${x}^{2} - (\alpha + \beta )x + ( \alpha \times \beta ) = 0$

${x}^{2} - 7x + 12 = 0$

$\tt{ {x}^{2} - 7x + 12 = 0 \: is \: the \: required \: qudratic \: equation}$