Question

a quadratic polynomial whose zeroes are -3and 4is​

Answer 1

Answer:-

Zeros - (-3),(4)

sum of zeros = (-3)+(4) = 1

product of zeros = (4)(-3) = (-12)

putting the values in the following equation:-

x²+(sum of zeros)x+(product of zeros)

x²+(1)x+(-12)

x²+x-12

Hope it helps you......

Answer 2

two roots are -3 and 4.

so , sum of roots = -3+4 = 1 .

and product of roots = -3(4) = -12.

now as , x^2-(sum of roots)x +product of roots=0 .

so ,x^2-(1)x+(-12)=0.

x^2-x-12=0 .....ans..