A quadratic polynomial, whose zeroes are -4 and -5 is ans. me fast then I will mark ur ans. as brainliest.
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Answered by
17
x^2 - (alpha+beta)x + alpha*beta
= x^2 - (-4-5)x + (-4*-5)
= x^2 + 9x + 20
Here’s your an :)
= x^2 - (-4-5)x + (-4*-5)
= x^2 + 9x + 20
Here’s your an :)
Answered by
41
GiveN:
- The zeroes of the quadratic polynomial are -4 and -5.
To FinD:
- Find the quadratic polynomial?
Step-by-step Explanation:
Let the zeroes of the quadratic polynomial be:
- α = -4,
- β = -5
Then,
α + β = -4 + ( -5) = -9
αβ = -4 × (-5) = 20
That means,
Sum of zeroes = α + β = -9
Product of zeroes = αβ = 20
Then, the quadratic polynomial
= x² - (sum of zeroes)x + product of zeroes
= x² - (-9)x + (20)
= x² + 9x + 20
Hence,
- The required quadratic polynomial is x² + 9x + 20.
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