Question

A quadratic polynomial whose zeroes are 5 and -3 is

Answer 1

Step-by-step explanation:

$\alpha = 5 \\ and \\ \beta = - 3 \\ \\ the \: form \: of \: quadratic \: equation \: is \\ {x}^{2} - ( \alpha + \beta )x + ( \alpha \beta ) = 0 \\ {x}^{2} - (5 + ( - 3))x + (5 \times - 3) = 0 \\ {x}^{2} - 2x - 15 = 0 \\ \\ therefore \: the \: quadratic \: equation \: is \: {x}^{2} - 2x = 15$

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Answer 2

Answer:

x²-2x-15

Step-by-step explanation:

The formula to find quadratic polynomials is

x²-x(sum of the zeroes) + product of zeroes

= 5

β = -3

x²-x(+β) + (β)

x²-x[5+(-3)] + (5) (-3)

x²-x(5-3) + (-15)

x²-x(2) + (-15)

x²-2x-15

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