Question

A quadratic polynomial whose zeroes are root 2 and root 6 / 2 are

Answer 1

Answer:

Q. P=

{x}^{2} - ( \alpha + \beta )x + \alpha \betax

2

−(α+β)x+αβ

{x}^{2} - ( - \sqrt{2} + \sqrt{2} ) + ( - \sqrt{2 } \times \sqrt{2} )x

2

−(−

2

+

2

)+(−

2

×

2

)

{x}^{2} - 2is \: the \: answerx

2

−2istheanswer

x^2-2 is the answer

Step-by-step explanation:

hope it is help ful

Answer 2

The quadratic polynomial whose zeroes are root 2 and √6/2

is x²-(2+√6/2)x+√6.

Given,

The zeroes of a quadratic polynomial are 2 and √6/2.

To Find,

The quadratic polynomial.

Solution,

The formula for calculating the quadratic polynomial when zeros are given is

x²-(sum of zeroes)x + product of zeroes.

Now, the given zeros are 2 and √6/2.

So,

Sum of zeroes = 2+√6/2 = 2+√6/2.

product of zeroes = 2(√6/2) = √6

Now, substituting the values

x²-(2+√6/2)x+√6

Hence, the quadratic polynomial whose zeroes are root 2 and √6/2

is x²-(2+√6/2)x+√6.

#SPJ2