Question

a quadratic polynomial whose zeros an
-3 and 4 is​

Answer 1

Answer:

alpha = -3, beta=4

(x+3) (x-4)

x(x-4)+3(x-4)

x^2-4x+3x-12

x^2-x-12 answer

Step-by-step explanation:

please please please mark me brainliest

Answer 2

Answer:

x^2 - x - 12 = 0                     (x^2 means x square)

Step-by-step explanation:

x= -3  and x= 4

x+3 = 0  and  x-4 = 0

(x+3)*(x-4) = 0

(x*x)+(3*x)+(x*-4)+(3*-4) = 0

x^2 + 3x - 4x -12 = 0

x^2 +(3-4)x -12 = 0

x^2 -x -12 = 0

you can check it by putting value of zeros(-3 or 4) in RHS (equation)

and you will get a ZERO ( 0 )

please like to appreciate our efforts

comment below for any doubt