Question

a quadratic polynomial whose zeros are - 3 and 4​

Answer 1

Answer:

As the roots are given considering them as alpha and beta you can find the equation by using

X^2-(alpha+beta)X+(alpha×beta)=0

X^2-(-3+4)X+(-12)=0

X^2-X-12=0

Step-by-step explanation:

Answer 2

Answer:

The correct answer of this question is $\frac{x^{2} }{2} - \frac{x}{2} - 6 = 0$

Step-by-step explanation:

Given - A quadratic polynomial.

To Find - Write a quadratic polynomial whose zeros are - 3 and 4​

A polynomial of degree two is called a quadratic polynomial. The form of a univariate quadratic polynomial is. A quadratic equation is an equation involving a quadratic polynomial.

Quadratic equation with α and β as roots are -

According to the question -

Here, α = −3 and β = 4

∴ α + β = −3 + 4 = 1

and α − β = −3 × 4 = − 12

Now, The quadratic equation is -

$x^{2}$ − (α+β) x + αβ = 0

$x^{2}$ − 1x − 12 = 0

$\frac{x^{2} }{2} - \frac{x}{2} - \frac{12}{2} = 0$

$\frac{x^{2} }{2} - \frac{x}{2} - 6 = 0$

Hence the quadratic polynomial is $\frac{x^{2} }{2} - \frac{x}{2} - 6 = 0$

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