A quadratic polynomial, whose zeros are -3 and 4 is *
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0
Answer:
x² - x - 12
Step-by-step explanation:
x = -3, x = 4
- (x - (-3))(x - 4) =
- (x + 3)(x - 4) =
- x² - 4x + 3x - 12 =
- x² - x - 12
Answered by
6
Solution -
The required Zeroes are -3 and 4 .
Sum of Zeroes -
=> -3 + 4
=> 1
Product Of Zeroes -
=> ( -3 )( 4 )
=> -12
Now , a quadratic polynomial can be written as -
x² - ( Sum of Zeroes ) x + ( Product Of Zeroes )
=> x² - ( 1 ) x - 12
=> x² - x - 12
Verification -
x² + x - 12
=> x² - 4x + 3x + 12
=> x ( x - 4 ) + 3 ( x - 4 )
=> ( x + 3 )( x - 4 )
Zeroes -
=> -3, 4
Hence Verified -
Additional Information -
In a Polynomial -
Sum of Zeroes = ( -b / a )
Product Of Zeroes = ( c / a )
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