Math, asked by anam5966, 7 hours ago


A quadratic polynomial whose zeros are 5 and -3, is
(a) +2x-15 (b) - 2x + 15 (c) - 2x-15 (d) none of these

Answers

Answered by LoverBoy346
0

Step-by-step explanation:

Let \:  \alpha  \: and \:  \beta  \: be \: the \: zeroes

Given

\bull \:  \:  \:  \alpha  = 5 \\ \bull \:  \:  \:  \beta  =  - 3

Sum \:  o f  \: zeroes =  \alpha  +  \beta  = 5 - 3 = 2

Product \:  of  \: its  \: zeroes =  \alpha  \times  \beta  = 5  \times ( - 3) =  - 15

We know that,

 {x}^{2}  - ( \alpha  +  \beta )x + ( \alpha  \times  \beta )

 {x}^{2}  - 2x  - 15 = 0

Verification

Sum \:  of  \: its \:  zeroes =  \frac{ - b}{a}  =  - ( - 2) = 2

Product  \: of \:  its \:  zeroes =  \frac{c}{a}  =  \frac{ - 15}{1}  =  - 15

Hence verified

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