Question

a quadratic polynomial whose zeros are -5and 4 is
1) x^2 -5x +4
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Answer 1

Answer:

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Answer 2

Answer:

x²-4x+4 =0

x²-4x-x+4 =0

x(x-4) -1(x-4) =0

(x-1) (x-4) = 0

x = 1,4

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$\alpha = - 5 \\ \beta = 4 \\ x = - 5 \\ x = 4 \\ ( x + 5) = 0 \\ (x - 4) = 0 \\ (x + 5)(x - 4) = 0 \\ {x ^{2} - 4x + 5x} - 20 = 0 \\ p(x) = {x}^{2} + x - 20 = 0$

Step-by-step explanation:

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