Question

a quadratic polynomial with sum and product of its zeros are 8 and -9 respectively is:a)x²–8x+9 b)x²–8x–9 c)x²+8x–9 d)x²+8x+9​

Answer 1

Answer:

option b

Step-by-step explanation:

sum of zeroes (S)= 8

product of zeroes (P)= -9

p(x)= k[x^2-Sx+P]

=k[x^2-8x+(-9)]

=k[x^2-8x-9]

Let k=1,

then, p(x)= x^2-8x-9