Question

a quadratic polynomials of the zeros of -3 and 4​

Answer 1

Answer:

The answer is x^2-x-12

Step-by-step explanation

Answer 2

Answer: x^2 +x-12

Step-by-step explanation:

alpha=-3,beta=4

alpha+beta= -b/a

1=-b/a

alpha*beta= c/a

-12=c/a

Polynomial= x^2 -(alpha+beta)x + alpha*beta=0

x^2-(-1)+-12=0

x^2+1x-12