Question

A quadratic polynomials whose one zero is -8 and sum of zeroes is 0 given then find the equation

Answer 1

Sum of zeroes = 0

First zero = - 8

Second zero = 0 - (-8) = 0+8 = 8


Product of zeroes = - 8* 8 = - 64



Required polynomial = x^2 - (sum of zeroes) x + Product of zeroes

= x^2 - 0x + (-64)

= x^2 - 64


Required polynomial = x^2 - 64

And equation is x^2 - 64 = 0

Answer 2

As the general equation is ...x^2-(sum of zeroes)x+(product of zeroes)..
Therefore ur equation will be x^2+0x-8...