A quadrilateral ABCD circumscribe a circle . Prove: AB+CD=AD+BC
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Answer:
refer below
Step-by-step explanation:
first as tangents are equal
there hlves are also equal so it ends up being like ab=cd and so on
then adding all of them in order to get
ae+be+cf+fd=al+ld+bq+qc
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Answer:
pls refer the above pic !
I hope this helps you !!!
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