Question

A quadrilateral ABCD circumscribes a circle with centre O. If angle AOB=125degree,then find angle COD

Answer 1

According to question

In triangle AOB

Angle AOB = 125 deg

Also in triangle COD

Angle COD = Angle AOB
  angle COD = 125 deg

As the angle are vertically opposite
So angle COD = 125 deg

Answer 2

Answer:

Step-by-step explanation:

We know, opposite sides of a quadrilateral circumscribing a circle subtend supplementary angle at the centre

Thus, 125 °+ Cod = 180

Cod = 55°