A quadrilateral abcd diagonal bd is bisected by diagonal ac prove that triangle abc and adc are equal in area'
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Given - BD = AC
TO PROVE - ar(abc) =ar(adc)
proof– ABCD Is a parallelogram (diagonal bisect each other )
In ∆abc and ∆adc
AB=DC (OPP. SIDE OF parallelogram)
BC = AD (SAME REASON)
AC=AC (COMMON )
therefore ∆ABC congruent ∆ABD
ar (ADC)= ar( ABC) [ congruent ∆are equal in area]
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