Question

A quadrilateral ABCD has all its angles of the
same measure. What is the measure of each
angle?
​

Answer 1

$\red{\underline{\underline{\textsf{\red{Given}}}}}$

$\sf{All\: four \:angles\: are\: same}$

$\red{\underline{\underline{\textsf{\red{To find:}}}}}$

$\sf{The \:measure \:of\: each\: angle}$

$\red{\underline{\underline{\textsf{\red{Concept: }}}}}$

$\small\begin{gathered}\begin{gathered}\\\;\underline{\boxed{\sf\;The\: sum \:of \:the \:angles\: of\: a \:quadrilateral =360^0}}\end{gathered} \end{gathered}$

$\red{\underline{\underline{\textsf{\red{Solution: }}}}}$

$\sf{Let\: the \:one\: angle\: be \:x}$

$\sf{x+x+x+x =360^0}$

$\sf{4x=360^0}$

$\sf{x=90^0}$

$\sf{Hence, \:each \:angle \:is\: equal\: to\: 90^0}$