A quadrilateral ABCD is circumscribed by a circle, If AB = 5cm, BC = 6cm,
CD = 7cm, then find the length of AD.
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Answer:
AB^2+ BC^2+ CD^2+AD^2
=5^2+6^2+7^2+×=360
=25+36+49+×=360
=110+×=360
=250 =×
is the correct answer
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