Question

A quadrilateral ABCD is drawn to circumscribe a circle. If AB = 15 cm, BC = 12 cm, CD = 13 cm,
then find the length of AD.​

Answer 1

Step-by-step explanation:

Given: Let ABCD is a quadrilateral which circumscribe the circle with center 'O'. The quadrilateral ABCD touches circle at point P , Q , R and S.

To Prove: AB+CD = AD+BC

Proof:

AP=AS…(i)

BP=BQ…(ii)

CR=CQ…(iii)

DR=DS…(iv)

Adding equation (i),(ii),(iii) and (iv) we get…

AP+BP+CR+DR=AS+BQ+CQ+DS

According to figure [AB=AP+PB, AD=AS+SD, CD=DR+CR, BC=BQ+CQ]

Or, AB+CD=AD+BC (Proved).

Hence,

AB+CD=AD+BC

Or, 12+14=AD+15

Or, AD=11 cm.

Answer 2

Answer:

11cm

Step-by-step explanation:

please mark me as the brainliest