A quadrilateral abcd is inscribed in a circle of radius 8 cm find the area of the quadrilateral
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A=πr2=π·82≈201.06193cm
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Answer:
(refer the attachment)
ar(ABCD) = ar(ABC) + ar(ADC)
= (1/2*AC*FB) + (1/2*AC*ED)
= (1/2*16*FB) + (1/2*16*ED)
= (8*FB) + (8*ED)
= (8*FB) + (8*FB) (FB=ED)
= 2(8*FB)
= 16FB
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