A quadrilateral ABCD is inscribed in a circle such that AB is a diameter and ∠ADC =
130°. Find ∠BAC
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Answer:
⇒ Quadrilateral ABCD inscribe in a circle.
∴ Quadrilateral ABCD is a cyclic quadrilateral.
⇒ ∠ADC+∠ABC=180
o
[ Sum of opposite angles of cyclic quadrilateral is supplementary ]
⇒ 130
o
+∠ABC=180
o
⇒ ∠ABC=180
o
−130
o
⇒ ∠ABC=50
o
Explanation:
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