Question

A quadrilateral has one of its diagonal 14.8 cm the altitudes drawn to this diagonal are 8.4 cm and 5.7 cm find its area

Answer 1

Answer:

104.34 cm^2

Step-by-step explanation:

• Let's divide the quadrilateral into two, and we will get two triangles.
• So,to find the area of triangle, we can find the areas of these triangles and add them.

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given,

• diagonal,AC =14.8cm
• DM. = 8.4 cm
• BN. =5.7 cm

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Area of triangle=(1/2)×base×height

• Area of ∆ABC

=(1/2)×AC×BN

=(1/2)×14.8×5.7

=42.18 cm^2

• Area of ∆ADC

=(1/2)×AC×DM

=(1/2)×14.8×8.4

=62.16cm^2

• Area of quadrilateral ABCD

=Area of∆ABC+Area of ∆ADC

=42.18+62.16

=104.34cm^2

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$\color{red}{hope \: it \: helps \: you}$