Question

A quadrilateral has one of its diagonals 14.8 cm the altitudes drawn to this
diagonal are 8.4 cm and 5.7 cm. Find its area

Answer 1

1/2×8.4×14.8= 62.16

1/2×5.7×14.8= 42.18

Answer 2

Answer:

104.34cm^

Step-by-step explanation:

Given:

One of the diagonal of the quadrilateral = 14.8 cm

Altitudes drawn to this diagonal are 8.4 cm and 5.7 cm.

To find:

The area of the quadrilateral

Solution:

We know that

The area of a quadrilateral is half the product of the length of one of its diagonal "d" and the sum of the length of altitudes "h₁" & "h₂" drawn from opposite vertices to that diagonal.

Area = 1/2×d×(h1+h2)

Here

d = 14.8 cm

h₁ = 8.4 cm

h₂ = 5.7 cm

Therefore, substituting the values in the formula, we get

Area of the given quadrilateral is,

= 1/2×14.8×(8.4+5.7)

= 1/2×14.8×14.1

= 7.4×14.1

= 104.34cm^

Thus, its area is 104.34 cm^.

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