A quadrilateral having a diagonal of length 10 cm, which divides the quadrilateral into two
triangles and the heights of triangles with diagonals as the base, are 4 cm and 6 cm. Find the
area of the quadrilateral.
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Solution:
Given,
Diagonal, d = 10 cm
Height of one triangle, h1 = 4cm
Height of another triangle, h2 = 6cm
Area of quadrilateral = ½ d(h1+h2) = ½ x 10 x (4+6) = 5 x 10 = 50 sq.cm.
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