Question

a quadrilateral in which AB is equal CD and AC is bisected by BD prove that area of triangle AOB is equal to triangle DOC​

Answer 1

Answer:

in the given figure

prove =

In quad. abcd

area of aob = ar(doc)

because and diagonal achi bisect to two triangle in equal part

thank for ask

Answer 2

In triangle DOC and AOB

AB=CD

OA=OC

Angle DOC = AOB( vertically opposite)

By SAS triangles are congurant

OD =OB(cpct)

As diagonals bisect each other therefore ABCD is a parallelogram.

CD//AB

Angle CDO is equal to angle O BA

Therefore triangle BOA similar to Triangle DOC

Area of triangleDOC / area of triangle BOA is equal to OA square upon OC square

OA= OC ( given )

Therefore area of triangle DOC is equal to area of triangle BOA