a quadrilateral is drawn to circumscribed a circle prove that the sums of opposite sides are equal
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Given: A quadrilateral ABCD in which a circle is circumscribed!
To prove: AB + CD = AD + BC
Proof: We know that, the tangents drawn from an external point to the circle are eual in length..
Therefore,
AP = AS
BP = BQ
CR = CQ
DR = DS
Adding all the above equations,
AP + BP + CR + DR = AS + BQ + CQ + DS
AB + CD = AD + BC
Hence proved!
Hope this helps! Thank you!
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