A quadrilateral is inscribed in a circle so that AB is the diameter of the circle if <ADC =105*,find m <BAC
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Answer:
Correct option is B)
Given:
ABCD is a cyclic quadrilateral with AB as the diameter of the circle.
Also, ∠ADC=140
o
.
We have to find: ∠BAC.
Then,
∠ADC+∠ABC=180
o
....(since the sum of the opposite angles of a quadrilateral is 180
o
).
∴∠ABC=180
o
−140
o
=40
o
.
Also, ∠ACB=90
o
....(since the angle subtended by a diameter at the circumference of the circle, is 90
o
).
∴ In ΔABC we have,
∠ACB=90
o
and ∠ABC=40
o
.
So, ∠CAB=180
o
−(∠ACB+∠ABC)
=180
o
−(90
o
+40
o
)
∴∠BAC=50
o
.
Hence, option B is correct.
Step-by-step explanation:
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