Question

a quadrilateral PQRS in which PQ = 4.6 cm QR = 5.3 cm < P = 60° , < Q = 100° and <R = 120°​

Answer 1

Answer:

Steps of Construction:

(i) Construct a line segment QR = 5 cm.

(ii) At the point Q, construct a ray QX making an angle of 60

⋅

and cut off QP = 4 cm.

(iii) At the point R, construct a ray RY making an angle of 90

⋅

and cut off RS = 4.5 cm.

(iv) Now join PS.

Therefore, PQRS is the required quadrilateral.