Question

a quadrilateral pqrs is drawn to circumscribe a circle. prove that pq+rs=ps+qr

Answer 1

I think it is helpful

Answer 2

Refer to the attachment for figure :)

AS=DS
AR=RB
CQ=BQ
CP=PD

$\bf{Reason}$ :- Tangents from external point are equidistant.


$\bf{Adding \:the\: adjacent \:sides }$



AS+AR+CQ+CP= DS+RB+BQ+PD

SR+PQ = DS+PD + RB+BQ

SR+PQ = PS + QR

$\bf{Or }$

PQ+RS = PS + QR

$\bf{\underline{Hence \:proved }}$

$\bf{Hope\:it\:helps}$☺