Question

A quadrilateral whose sides are 3cm, 4cm, 4cm, 5cm and one of the diagonal is equal to 5cm. The area of the quadrilateral is. ​

Answer 1

இனிய இரவு நாளை சந்திக்கலாம்

Answer 2

Answer:

Step-by-step explanation:

Take triangles ABC and ADC

i) ΔABC

Area = $\sqrt{s(s-a)(s-b)(s-c)$

S= $\frac{a+b+c}{2}$

S= $\frac{3+4+5}{2}$= 6cm

A=$\sqrt{6(6-3(6-4)(6-5)}$

A= $\sqrt{6*3*2*1}$

A= $6cm^{2}$

ii) ΔADC

A=  $\sqrt{s(s-a)(s-b)(s-c)}$

S= $\frac{5+5+4}{2}$

S= $7cm^{2}$

A= $\sqrt{7(7-4)(7-5)(7-4)}$

A=$\sqrt{7*2*2*3}$

A= $9.16cm^{2}$

Area of quadrilateral =  i + ii

                                   = $6cm^{2} + 9.16cm^{2}$

                                   = $15.16cm^{2}$