A quadrilateral whose sides are 3cm, 4cm, 4cm, 5cm and one of the diagonal is equal to 5cm it's area is
Answers
Given : A quadrilateral whose sides are 3cm, 4cm, 4cm, 5cm and one of the diagonal is equal to 5 cm
To Find : The area of the quadrilateral
Solution:
Quadrilateral can be divided in 2 triangle
one with sides 3 , 4 , 5 cm
and another with sides 4 , 5 , 5 cm
Area of Quadrilateral = area of both triangle
Triangle with sides 3 , 4 , 5 cm is right angle triangle as (3 ,4 , 5) is Pythagorean Triplet
Hence area = (1/2) * base * Height
= (1/2) * 3 * 4
= 6 cm²
Triangle with sides 4 , 5 , 5 cm
s = ( 4 + 5 + 5)/2 = 7
Area of triangle using Hern's formula
= √7(7 - 4)(7 - 5)(7 - 5)
= √7(3)(2)(2)
= 2√21
≈ 9.16 cm²
Area of the Quadrilateral ≈ 6 + 9.16 ≈ 15.16 cm²
Learn More:
find the area of triangle having vertices at (8,1)
brainly.in/question/12350448
Find the area of quadrilateral whose vertices are (–5, 7), (–4, –5 ...
brainly.in/question/16977940
The vertices of a A ABC are A(-5, -1), B(3.-5), C(5,2).
brainly.in/question/8993582
