Question

A quantity has a value of -6.0m/s. It may be the
speed of a particle velocity of a particle
position of a particle
displacement of a particle

Answer 1

Answer:

A particle moves along the positive branch of the curve Y^2=2X where X=T^2/2. What is the acceleration of the particle at T=2

Explanation:

value of -6.0m/s.0-t is vavg = ( v+ u)/2.