Question

A quantity of 10g a hydrocarbon exactly requires 40 g oxygen for complete computation. The products formed are CO2 and water. When CO2 gas formed is absorbed completely in lime water the mass of solution increases by 27.5g. what is the mass of water formed simultaneously in the combustion?

Answer 1

Answer:

[tex]Hydrogen + Oxygen → Carbon dioxide + 

Water

[tex]Hydrogen + Oxygen → Carbon dioxide +  Water↓                            ↓ 

[tex]Hydrogen + Oxygen → Carbon dioxide +  Water↓                            ↓ 10 gm                 40 g

[tex]Hydrogen + Oxygen → Carbon dioxide +  Water↓                            ↓ 10 gm                  the mass of soln increases by 27.5 gm

[tex]Hydrogen + Oxygen → Carbon dioxide +  Water↓                            ↓ 10 gm                 40 gAs when CO2 is absorbed in lime water, the mass of soln increases by 27.5 gm∴ Mass of CO2=27.5 gm

[tex]Hydrogen + Oxygen → Carbon dioxide +  Water↓                            ↓ 10 gm                 

 [tex]Hydrogen + Oxygen → Carbon dioxide +  Water↓                            ↓ 10 gm                 40 gAs when CO2 is absorbed in lime water, the mass of soln increases by 27.5 gm∴ Mass of CO2=27.5 gm∴ Mass of H2O= (Mass of hydrogen + Mass of oxygen − mass of CO2)=(10+40−27.5) gm=22.5 gm

[

Explanation:

Please Mark as Brainliest