Question

A quantity of 1kgbof 1 molar glucose solution is dilluted to 5 kg .The molality of the diluted solution should be

Answer 1

Answer:

THE ANSWER IS 0.2m

Explanation:

Let mass of C6H12O6 be x (gm) in 1 molal solution.

Then x18010001000−x=1 (Molar mass of C6H12O6 is 180gm)

Hence x=1800001180≈152.54

Now diluted solution weighs 5kg. Upon dilution, number of moles of glucose (or mass of glucose) remains unchanged. Hence the mass of solvent becomes 5000−152.54gm=4847.46gm

Hence molality of resulting C6H12O6solution will be :

m=152.5418010004847.46molkg−1

m = 0.17 molal  

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