Question

A quantity of aluminium has mass of 54.0g. What is the mass of same number of magnesium atoms?

Answer 1

n(Al)= 54/27
n(Al)=n(Mg)
54/27=x/24
[x=48g]

Answer 2

Answer:

$\huge\mathfrak\green{{Here~is~your~Answer}}$

Mole $= \frac{given \: mass}{molar \: mass}$

Then, moles of aluminum $= \frac{54}{27}$$= 2$

According to question,

For 2 moles of magnesium it's mass is $2 × 24 = 48g$

Hence, the required mass for same number of magnesium atoms is 48g.

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