Question

A quantity of aluminum has a mass of 54.0g. What is the mass of the same number of magnesium atom?

Answer 1

1 mole of Al = 27 g
therefore, no of moles in 54 g of Al
n=m/M
n=54/27
n=2 moles
now,
1 mole of Mg = 24 g
therefore 2 moles of Mg=?
m=Mn
m=24 g

Answer 2

Answer:

$\huge\mathfrak\green{{Here~is~your~Answer}}$

Mole $= \frac{given \: mass}{molar \: mass}$

Then, moles of aluminum $= \frac{54}{27}$$= 2$

According to question,

For 2 moles of magnesium it's mass is $2 × 24 = 48g$

Hence, the required mass for same number of magnesium atoms is 48g.

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