Question

A quantity of hydrogen gas occupies a volume of 30.0mL at a certain temperature and pressure. What volume of half of this mass of hydrogen occupy at triple the absolute temperature if the pressure were one-ninth the original gas?

Answer 1

P×30=n1×R×TP×30=n1×R×T

If half of the mass of hydrogen occupy at triple the absolute temperature if the pressure were one-ninth the original gas,

P9×V=n12×R×3TP9×V=n12×R×3T

V=9×30×32V=9×30×32

=405mL