Question

A quantity of oxygen occupies a volume of 500ml at 27°C. At which temperature
does the volume become double? (Pressure remains same) (Ans: 327°C)​

Answer 1

Answer:

Given,

Volume 1 (V₁) = 500 mL

Temperature (T₁) = 27°C

= (27+273) K

= 300 K

Volume 2 (V₂) = 2V₁

= (2*500) mL

= 1000 mL or, 1 L

By Charles's Law,

V₁/T₁ = V₂/T₂

= 500/300 = 1000/T₂

= 500T₂/300 = 1000

= T₂ = (1000*300)/500

= T₂ = 300000/500

= T₂ = 600 K

or,

= T₂ = (600-273) °C

= The New Temperature will be = 327°C

I hope this helps.