a quantity of tea is sold at rupees 48 per kg at a profit of 20 % the total gain is rupees 90 what is the quantity of tea sold?
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Let the quantity sold be x
20% 0f 48x = 90
48x = 90(100/20)
48x= 450
x= 9.375kg
x≈9kg
20% 0f 48x = 90
48x = 90(100/20)
48x= 450
x= 9.375kg
x≈9kg
teaquestion:
sorry but in mt book the answer is 11.25 i want tge answer according to the profit \ formula
Okay then
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0
Gain per kg
= 20 % of 48
= (20/100) × 48
= 48/5
Hence there is gain of Rs. 48/5 per 1 kg
let the gain of 90 Rs be for x kg
48/5 = 90/x
x = (90×5)/48
x = 9.37 kg
________________
= 20 % of 48
= (20/100) × 48
= 48/5
Hence there is gain of Rs. 48/5 per 1 kg
let the gain of 90 Rs be for x kg
48/5 = 90/x
x = (90×5)/48
x = 9.37 kg
________________
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